5t^2=31t=28

Solution for 5t^2=31t=28 equation:

5t^2=31t=28

We move all terms to the left:

5t^2-(31t)=0

a = 5; b = -31; c = 0;
Δ = b2-4ac
Δ = -312-4·5·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-31}{2*5}=\frac{0}{10}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+31}{2*5}=\frac{62}{10}
=6+1/5
$